Lecture 50 · Performance
Last cards match
Video in production
This lecture is still face down. Its script is written; filming and animation are under way.
Meanwhile, play the trickWhat you will learn
Perform a checked opposite-order packet matching routine using fixed-total rotations and elimination.
Before this lecture
Nothing. This lecture is a fine place to start.
In this lecture
An outline of the lecture, scene by scene, with the statements that appear on screen. It follows the draft script, so details may change in production.
Perform first elimination
At the table- Move top→bottom in same packet
- 11 moves total
Repeat at smaller sizes
At the table- Sizes 4→3→2→1
Reveal the matching pairs
At the table- Last ranks match
Derive top-index relation
- Match iff a+b ≡ m−1 (mod m)
Track an exact sample
- (3, 8); (5, 6); (4, 7)
Prove preservation after removal
- Matched removal restores reverse order
Explain the fixed total
- T+1 divisible by 4, 3, 2
- lcm(4, 3, 2)=12
Play and retrieve
- Fixed total; free allocation
Companion interactive
Choose every rotation side and explain why matching survives each elimination.
The trick page is this lecture’s companion: be the spectator, lift the curtain to step through why it works, try the challenge, then learn the handling.
Sources
- “Chinese Remainder Theorem and Cards (Tadashi Tokieda)” (video) · link
How these sources were used
- Opposite-order last-card matching inspiration. Exact four-rank rotation/elimination version and count rule derived and checked; no sleight or COAT reversal.